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- Homework Statement
- A car of mass ##850## kg is travelling with acceleration ##0.3 m/s^2##, up a straight road inclined at ##12^0## to the horizontal. There is a force resisting motion of ##250## N. Calculate the magnitude of the driving force.

- Relevant Equations
- Resolving forces- Mechanics

My approach is as follows, let ##D## be driving force and ##F## the force resisting motion, then

##D-F = 850 × 0.3##

##D = 250 + 255##

##D = 505##

Also, Force parallel to the road is given by, ##F_1 = 8500 \cos 78^0 =1767.24 N##

Therefore, the magnitude of Driving force is given by, ##F_1 + D = 2272.25 N##

your insight is welcome...not sure on this...

##D-F = 850 × 0.3##

##D = 250 + 255##

##D = 505##

Also, Force parallel to the road is given by, ##F_1 = 8500 \cos 78^0 =1767.24 N##

Therefore, the magnitude of Driving force is given by, ##F_1 + D = 2272.25 N##

your insight is welcome...not sure on this...