Calculate the net force on the central charge

[collegekid420]

Homework Statement

A square of side 1cm has a charge of q= 1uC at its center. The four vertices of the square have charges distributed equally. Calculate the net force on the central charge.
A. Find the distance from the central charge to the equidistant charges
B. Find the force of interaction between the central charge and one of the charges at the vertices
C. Find the magnitude of the net force on the central charge.

Homework Equations

F=((k)*abs(qQ))/(d^2)

The Attempt at a Solution

A. I found the distance ((2)^1/2)/(2) to be right
B. F= (9*10^9)(1*10^-3C)(1*10^-6C)/(.014m)^2 <--- is this correct?

C. How do you find this?

 

[Jhero]

Dear fellow scientist,

Thank you for your post. I would like to provide some feedback on your approach to finding the net force on the central charge.

A. Your calculation for the distance is correct. Great job!

B. Your formula for calculating the force of interaction between two charges is also correct. However, I believe there may be a mistake in your calculation. The distance should be the same for all four charges at the vertices, which is 1cm or 0.01m. Can you double check your calculation using this distance?

C. To find the net force on the central charge, we need to consider the forces from all four charges at the vertices. Since the charges are distributed equally, we can calculate the force from one charge and then multiply it by four. So, the net force would be:

Fnet = 4*(9*10^9)(1*10^-3C)(1*10^-6C)/(0.01m)^2

I hope this helps. Keep up the good work!