A thin 8.0 kg wheel of radius 28 cm is weighted to one side by a 5 kg weight, small in size, placed 10 cm from the center of the wheel. (a) Calculate the position of the center of mass of the weighted wheel. choosing the 8.0kg wheel to be on the origin, my cm is (8.0*0+5*0.1)/(8+5). (b) Calculate the moment of inertia about an axis through its center of mass, perpendicular to its face. How do I do that?