A thin 8.0 kg wheel of radius 28 cm is weighted to one side by a 5 kg weight, small in size, placed 10 cm from the center of the wheel.(adsbygoogle = window.adsbygoogle || []).push({});

(a) Calculate the position of the center of mass of the weighted wheel.

choosing the 8.0kg wheel to be on the origin, my cm is (8.0*0+5*0.1)/(8+5).

(b) Calculate the moment of inertia about an axis through its center of mass, perpendicular to its face.

How do I do that?

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# Homework Help: Calculate the position of the center of mass of the weighted wheel

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