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Calculate the slit width

  1. Mar 30, 2016 #1
    1. The problem statement, all variables and given/known data
    When 450nm light falls on a slit, the central diffraction peak (central maxima) on a screen 2.0m away is 6cm wide. Calculate the slit width?
    wavelength= 450 x 10^9m
    L= 2m
    y= 0.06m
    w=?
    2. Relevant equations
    y/L = tantheta = sintheta
    sintheta = (m+1/2)lambda / w



    3. The attempt at a solution
    I attempted at this, and got this answer... can anyone check to see if I did it right?
    y/L = sintheta
    0.06/2 = 0.03

    sintheta = (m+1/2)lambda / w
    0.03 = (1+1/2) (450 x 10^-9) / w
    w= 2.25 x 10^-5m
     
  2. jcsd
  3. Mar 30, 2016 #2

    blue_leaf77

    User Avatar
    Science Advisor
    Homework Helper

    You are using a wrong formula. It should be ##\sin\theta = m\lambda / w##.
     
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