- #1
Sunsing
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Homework Statement
A liquid (p = 1.65 g/cm3) flows through two horizontal sections of tubing joined end to end. In the first section the cross-sectional area is 10.0 cm2, the flow speed is 265 cm/s, and the pressure is 1.20 x10^5 Pa. In the second section the cross-sectional area is 3.50 cm2.
a) Calculate the smaller section's flow speed. 7.67m/s
(b) Calculate the smaller section's pressure. ?
Homework Equations
p=1.65g/cm^3 =.00165kg/cm^3
A1=10cm^2
v1=265cm/s
P1=1.2x10^5pa
A2=3.5cm^2
V2=7.67m/s = 767cm/s
P2=?
P1+1/2pv1^2=P2+1/2pv2^2
The Attempt at a Solution
I'm getting an incorrect answer for P2 in question b, but I'm not sure what I'm doing wrong.
I got 1.19**10^5, but that is incorrect. Any ideas?
Thank you