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Here is the problem that am working on.

A stone is thrown vertically upward with a speed of 12.0 m/s from the edge of a cliff 70 m high.

(a) How much later does it reach the bottom of the cliff?

(b) What is its speed just before hitting

(c) What total distance did it travel.

I have calculated the total time it takes to reach the bottom of the cliff, but haven't been able to do the (b) and (c) part. Here is what i have done

I used this formula to compute the time and am getting it right.

x= x(0) + v(0)t + 1/2 at^2

0= 70+12t+1/2(-9.8)t^2

t= 5.2 seconds, -2.75 seconds

the ans to the c part is 84.7m and b part is38.9 m/s. Please suggest me a hint. Thanks

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# Homework Help: Calculated the total time kinematics

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