Hi,(adsbygoogle = window.adsbygoogle || []).push({});

Here is the problem that am working on.

A stone is thrown vertically upward with a speed of 12.0 m/s from the edge of a cliff 70 m high.

(a) How much later does it reach the bottom of the cliff?

(b) What is its speed just before hitting

(c) What total distance did it travel.

I have calculated the total time it takes to reach the bottom of the cliff, but haven't been able to do the (b) and (c) part. Here is what i have done

I used this formula to compute the time and am getting it right.

x= x(0) + v(0)t + 1/2 at^2

0= 70+12t+1/2(-9.8)t^2

t= 5.2 seconds, -2.75 seconds

the ans to the c part is 84.7m and b part is38.9 m/s. Please suggest me a hint. Thanks

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Calculated the total time kinematics

**Physics Forums | Science Articles, Homework Help, Discussion**