The correct way is [tex]\left(\begin{array}{cc}13\\1\end{array}\right \left(\begin{array}{cc}4\\2\end{array}\right [/tex](12;3)(4;1)(4;1)(4;1)(adsbygoogle = window.adsbygoogle || []).push({});

But why does (13;1)(4;2)(48;1)(44;1)(40;1) fail? I would have thought that after you get the two that match there are 48 left to choose from that don't macht, and 44 that don't macht, and so on.

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# Calculating a pair in Poker

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