Calculating Attraction Between Cokes: Solve the Puzzle

[Izekid]

I don't know how to do this, 2 Cokes standing 35 cm from each other, Calculate the attraction to each other. One can weights 365grams.

Ok I know we should use G*m1m2/r1 and I have tried that and the result becomes only wrong like this

0,365*0,365 / 0,35 =0,3806428571 * 6,67*10^-11 =2,53888786^-11

Well that's not right the answer should be 7,3*10^-11

 

[Doc Al]

Ok I know we should use G*m1m2/r1 ...

That should be:
$$\frac{G m_1 m_2}{r^2}$$

 

[Izekid]

thx for that much easier now

 

[Izekid]

Got another one here too, The Electron in the Hydrogenatom has a mediumdistans of 5*10^-11 Calculate the gravitationsforce on the electron from the protone in the middle. How shall i calculate this when I aint got the mass

 

[Doc Al]

Look up the masses of the proton and electron!