(adsbygoogle = window.adsbygoogle || []).push({}); Calculating Centripetal Force?!? (car moving in circle on a sloped road)

Hi guyz,

i have problem with this IB standard level mechanics question:

here is the link 2 the question: (it is from an International Bacalaureatte examination):

http://img494.imageshack.us/img494/4303/motionofcar5xa.png [Broken]

The markscheme (answer sheet) has this as the way they got their answer:

horizontal component = R sin14;

= 8500 tan14;

= 2119 N --> which approx is 2100 N

my area of concern is how they arrived at the value for R, here is my calculation

x = 14 degrees, R = Reaction force of the road on the car, F = Horizontal component of the force R

http://www.rahmahwear.com/mymethod.doc [Broken] [in this file]

i understand how they got their answr in teh markscheme, but what's the error in my logic?

as for partd, i thought that if velocity increase, F will increase (i.e. for example.. instead of 2100 it become 3000 but it is still towards center of circle), therefore the car should slide DOWN the ramp?, they say that

"friction must supply larger force2ward center, car tends to slide UP he ramp"

sorry i couldnt ask my own physics teacher.. he's a great bludger.

Thanks in advance

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# Homework Help: Calculating Centripetal Force? (car moving in circle on a sloped road)

**Physics Forums | Science Articles, Homework Help, Discussion**