Insights Blog
-- Browse All Articles --
Physics Articles
Physics Tutorials
Physics Guides
Physics FAQ
Math Articles
Math Tutorials
Math Guides
Math FAQ
Education Articles
Education Guides
Bio/Chem Articles
Technology Guides
Computer Science Tutorials
Forums
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Trending
Featured Threads
Log in
Register
What's new
Search
Search
Search titles only
By:
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Menu
Log in
Register
Navigation
More options
Contact us
Close Menu
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Forums
Homework Help
Biology and Chemistry Homework Help
Calculating concenteration at equilibrium
Reply to thread
Message
[QUOTE="harambe, post: 6064240, member: 643357"] [h2]Homework Statement [/h2] 0.1mole of N2O4 (g) was sealed In a tube under one atmospheric conditions at 25°C.Calculate the number of moles of NO2(g) present if the equilibrium N204(g) --->2NO2(g) (Kp=0.14) is reached after some time [h2]Homework Equations[/h2] K=[NO2]^2/[N2O4] [B]3. The attempt at the solution [/B] N204(g) --->2NO2(g) O. 1 0 O. 1-x x Converting Kp into Kc gives me Kc=0.00572 Kc[NO2]^2/[N2O4]V where V is the volume But I don't know the volume so I am not able to calculate here.. . Any hint on how to solve this [/QUOTE]
Insert quotes…
Post reply
Forums
Homework Help
Biology and Chemistry Homework Help
Calculating concenteration at equilibrium
Back
Top