- #1

- 91

- 0

## Homework Statement

Iron sample with dimensions 10mm x 20mm x 2mm is exposed to a corrosive environment (neglect thickness for surface area). Both sides of the sample are exposed to corrosive environment. Given http://i.imgur.com/tGRw4.jpg"

(a) Calculate corrosion rate mm/y

(b) Calculate corrosion rate if one of the sample surfaces is painted (not in contact with corrosive environment)

## Homework Equations

M=56g,

t=3.1536e7 sec/yr

number of electrons taking part n=2

F=96500C

density=7.87g/cm3

A=10*20=200mm2

From Faraday's Law: W=MtI/nF (W=weight loss, I=current in this case corrosion current)

## The Attempt at a Solution

(a) From Tafel Plot log(Icorr)=0.05mA/cm2 so Icorr=1.12e-3 A/cm2

I want to convert Icorr to just units of A, but since both surfaces are exposed should I multiply it by double the surface area?

i.e.: Icorr=1.12e-3*200mm2*2*(1cm/10mm)^2 = 4.48e-3 A

substituting in W=Mt*Icorr/nF = 40.99 g/yr

Corrosion Rate CR=W/density*Surface Area

Again I multiplied the Surface Area by 2 because both sides of the Iron sample is exposed

CR=(40.99g/yr)/[(7.87g/cm3)*(200mm2*2)*(1cm/10mm)^3)]=13.02mm/yr

(b) For only one side exposed:

I'm going to use half of Icorr since only 1 side is exposed so Icorr=2.24e-3 A

then W=20.49g/yr

Using only 200mm2 as the surface area

CR=(20.49g/yr)/[(7.87g/cm3)*(200mm2)*(1cm/10mm)^3)]=13.02mm/yr

I get the same corrosion rate...is this correct?

I believe the issue is with the surface area, I'm not sure if it effects the Icorr?

Last edited by a moderator: