Calculating Coulombs law

  • #1

Main Question or Discussion Point

The law I am talking about is F=K* (qa*qb / r2) I know the values of all but I have a question on the q's which represent the electrical charges...
If the charge is +2/3 do I plug in the fraction 2/3 in the q's spot? is this the numerical number I use? PLEASE HELP!!!
 

Answers and Replies

  • #2
Andrew Mason
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The law I am talking about is F=K* (qa*qb / r2) I know the values of all but I have a question on the q's which represent the electrical charges...
If the charge is +2/3 do I plug in the fraction 2/3 in the q's spot? is this the numerical number I use? PLEASE HELP!!!
Are you trying to find the coulomb force between two charges of +2e/3?

AM
 
  • #4
Vanadium 50
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OK, so what unit is charge measured in? How much is e in those units? So how much then is 2/3e?
 
  • #5
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The law I am talking about is F=K* (qa*qb / r2) I know the values of all but I have a question on the q's which represent the electrical charges...
If the charge is +2/3 do I plug in the fraction 2/3 in the q's spot? is this the numerical number I use? PLEASE HELP!!!
If both of the charges are +2/3 C, then you just plug in the charges for q

F = KQQ / R^2
F = (8.98e9)(2/3)^2 / R^2

The units for charge are Coulombs.
 
Last edited:
  • #6
ok thanks
 

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