When a certain light beam strikes a certain metal, 1 eV electrons are liberated. If the beam is replaced by one of half the original wavelength, 5 eV electrons are liberated. What is the energy of the photons in the original beam?
Part of my confusion with this problem is I don't know of any formula that can tell me this information. The only formula that references wavelength that I've seen in class is E = hc/L where hc is a conversion factor equal to 1240 eV*nm.
The Attempt at a Solution
I guess I need to find out the relationship between liberating electrons and energy. When the wavelength is reduced to 1/2 L, it increases the amount of liberated electrons to 5 eV. Unfortunately, my class has no textbook, so it's very hard for me to figure this out on my own. If anyone can help me out, I'd very much appreciate it!