• Support PF! Buy your school textbooks, materials and every day products Here!

Calculating Equilibrium Pressures

  • Thread starter Youngster
  • Start date
  • #1
38
0

Homework Statement



For the reaction

2 NO[itex]_{2}[/itex](g) [itex]\leftrightarrow[/itex] N[itex]_{2}[/itex]O[itex]_{4}[/itex](g)

ΔH°[itex]_{rxn}[/itex] = -57.2 kJ and ΔS°[itex]_{rxn}[/itex] = -175.8 [itex]J/K[/itex]

A 1 L container is initially filled with 1 atm of NO[itex]_{2}[/itex] at 298 K. Find the equilibrium pressures of NO[itex]_{2}[/itex] and N[itex]_{2}[/itex]O[itex]_{4}[/itex] at 298 K if

a. volume is held constant

b. pressure is held constant

Homework Equations



dG = VdP - SdT

The Attempt at a Solution



So using the fundamental thermodynamic equation above, I found that ΔG = -4811.6 J. SdT goes to zero since the temperature doesn't appear to change. VdP can be substituted withdH -TdS, with all three values available in the problem.

So using the following relation between K[itex]_{eq}[/itex] and free energy:

ΔG°[itex]_{rxn}[/itex] = -RTln(K[itex]_{eq}[/itex])

Solving for K[itex]_{eq}[/itex], I obtain 6.973

So from this point, how do I calculate the partial pressures of NO[itex]_{2}[/itex] and N[itex]_{2}[/itex]O[itex]_{4}[/itex]? Can I stop at 6.973?

As for the second question, I find that if pressure is held constant, the equilibrium constant is just 1, since ΔG[itex]_{rxn}[/itex] goes to zero.
 

Answers and Replies

  • #2
20,143
4,210
How is the equilibrium constant expressed in terms of the partial pressures of NO2 and N2O4? Also note that the standard heat of reaction and standard entropy change of reaction are evaluated at constant pressure (1 atm), not constant volume. So the problem you have been working on is really problem 2. You have yet to address problem 1.
 

Related Threads on Calculating Equilibrium Pressures

  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
3
Views
3K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
3
Views
7K
  • Last Post
Replies
19
Views
2K
Replies
2
Views
3K
Replies
3
Views
893
Replies
2
Views
875
Replies
24
Views
4K
Replies
4
Views
1K
Top