1. The problem statement, all variables and given/known data The 14mm diameter steel bolt with modulus of elasticity of 210GPa and modulus of rigidity of 85 GPa shown in the diagram below holds two components together. The thickness of the bolted interface of the components is 18mm. To 2 decimal places, for the given loading; Assuming the ultimate tensile stress is 490MN/m2 and the ultimate shear stress is 290MN/m2 determine the factor of safety in operation. Forces - http://imgur.com/mbTD0Xg 2. Relevant equations Assuming the ultimate tensile stress is 490MN/m2 and the ultimate shear stress is 290MN/m2 determine the factor of safety in operation. 3. The attempt at a solution I have resolves the forces and found the following Direct Stress 35.12 Mpa Tensile Stress 0.17 Mpa (I think something may be amiss here) Sheet Stress 26.24 Mpa But for the factor of safety the notes I have been given say to divide the UTS by the direct stress, So 490/35.12 = 13.95 (seems rather high). But then do I repeat for the Ultimate sheer stress? So again 290/35.12 = 8.26. Then is the lower of the two value? Any help is greatly appreciated.