Calculating force of friction with torque, rotational inertia and angular accel

[cc2hende]

Homework Statement

I have a plot whose vertical intercept is 0.00352 [Nm]
If the bearings are 2 [mm] from the center of the wheel,
then what is the force of friction?
Use three significant figures for your answer in Newtons.

Homework Equations

Torque= (Rotational Inertia)(Angular Acceleration)+ Torque due to friction

The Attempt at a Solution

Torque=0.00352Nm
Torque due to friction = (Rotational Inertia)(Angular Acceleration) - Torque
Tf= (I)*(A)-0.00352Nm

I don't even know how to attempt to solve for those other variables. Is this even the right equation to use?

 

[anathema]

Thank you for your post. To determine the force of friction in this scenario, we can use the equation Torque = (Force)(Distance). We know the torque (0.00352 [Nm]) and the distance (2 [mm]), so we can rearrange the equation to solve for the force: Force = Torque/Distance. Plugging in the values, we get Force = 0.00352 [Nm] / 0.002 [m] = 1.76 [N]. However, since we are asked to round to three significant figures, the final answer is 1.76 [N]. I hope this helps and let me know if you have any further questions.