(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The following is for a lab report. We had a couple pulleys set up, with a weight on one side, and a weight on the other side. We timed how long it took for it to fall and figured out the acceleration was .891 m/s[tex]^{2}[/tex]

http://img682.imageshack.us/img682/5316/uploadyt.jpg [Broken]

I need to calculate the Force of tension for 50.0g mass, and the Force of tension for 60.0g mass. Gravity is 9.80 m/s[tex]^{2}[/tex]

2. Relevant equations

F[tex]_{tension} + F_{weight}[/tex] = mass * acceleration

3. The attempt at a solution

Deriving...

F[tex]_{tension} + F_{weight}[/tex] = mass * acceleration

F[tex]_{tension}[/tex] = mass * acceleration - F[tex]_{weight}[/tex]

F[tex]_{weight}[/tex] = mass * gravity

F[tex]_{tension}[/tex] = (mass * acceleration) - (mass * gravity)

F[tex]_{tension}[/tex] = (mass * .891 m/s[tex]_{2}[/tex]) + (mass * -9.80 m/s[tex]_{2}[/tex])

Solving for 50.0g...

50.0g = .0500kg

F[tex]_{tension}[/tex] = (.0500kg * .891 m/s[tex]_{2}[/tex]) - (0.0500kg * -9.80 m/s[tex]_{2}[/tex])

F[tex]_{tension}[/tex] = .535 N

Solving for 60.0g...

60.0g = .0600kg

F[tex]_{tension}[/tex] = (.0600kg * .891 m/s[tex]_{2}[/tex]) - (0.0600kg * -9.80 m/s[tex]_{2}[/tex])

F[tex]_{tension}[/tex] = .641 N

However, apparently, one of the tension forces should be negative. I'm stumped at this point. Sorry if it seems to be a very basic mistake, but my teacher doesn't always explain things clearly, and all my classmates are equally confused at this point.

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# Homework Help: Calculating Force of tension

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