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## Homework Statement

Car tires have a coefficient of friction of .06 and the tires are accelerating at 5/ms^2. If the total mass of the car is 500 kgm, calculate the forward force exerted by the car engine.

## Homework Equations

I know that .06 is Mu and Mu is equal to friction/normal force. And I know that force=m*a.

## The Attempt at a Solution

I sometimes get confused with the difference forces. I calculated the forward force to be 2500 N by doing f=(500)(5). But I'm not sure if that's right because isn't this equation only for normal force? Can it also be for forward force?

Then I did .06=friction/2500 and I got 150 N for friction. So if friction is 150 N and forward force is 2500 then the net forward force exerted by the car engine would be 2350 N.

Is this correct? I have a feeling it's not...