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Calculating Free Energy

  1. Apr 13, 2006 #1
    Calculate the gibbs free energy for a reaction which has a standard enthalpy = -196kJ/mol and standard entropy = 151 J/K mol at 32C.

    G = -196 KJ/MOL -[-305.15 K*0.15] = -242KJ

    Thank you.
     
  2. jcsd
  3. Apr 13, 2006 #2
  4. Apr 13, 2006 #3
    Isn't that what I did?
     
  5. Apr 13, 2006 #4

    dav2008

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    Gold Member

    You're adding kiloJoules to Joules...
     
  6. Apr 13, 2006 #5
    No, I think he did not. Because he converted 151 J to 0.15 kJ:

     
  7. Apr 13, 2006 #6

    dav2008

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    Gold Member

    Oops didn't notice that.
     
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