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- Thread starter SignSeeker7
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- #1

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- #2

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V^2/R

Velocity in m/s with that number squared divided by the radius in meters.

Velocity in m/s with that number squared divided by the radius in meters.

- #3

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V^2/R

Velocity in m/s with that number squared divided by the radius in meters.

So, G-Force is the same as centripetal acceleration?

- #4

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So, G-Force is the same as centripetal acceleration?

"G force" is just the ratio of a given force to the force due to gravity on the same object. Think of it as a unit of measure, it's not a special kind of force. Typically, "G forces" are referring to pseudo forces experienced in an accelerating reference frame.

Now, if you wanted to know the gravitational attraction between two objects, then you'd use Newton's law of gravitation.

- #5

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So, G-Force is the same as centripetal acceleration?

Yes, if you are going in a circle, or even changing direction. You can also get g force from linear acceleration. If you were in a rocket that could accelerate at 4 g's straight up, or 39.2 m/sec^2 you would be subject to 5 g's. Four from the rocket and one from the Earth.

- #6

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8^2=64

64/15=approximately 2.67.

So now, you have your m/s^2 for the acceleration.

2.67/9.8 m/s^2 (9.8 m/s^2 is the acceleration of the Earth's gravity)=.2724

So, we can now see that the centripetal force on a merry go round rider with that velocity around a circle with that radius, we are feeling .2724 G's of acceleration, or 27.24% of Earth's gravitational pull.

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