Calculating grams of Precipitate

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Homework Statement


If 70.0 mL of 0.150 M CaCl2 is added to 15.0 mL of 0.100 M AgNO3, what is the mass in grams of AgCl precipitate?

Homework Equations


Limiting reagants.

The Attempt at a Solution


So I tried to find the limiting reagent, but that's where I'm stuck. I'm using examples from my textbook and notes, but everything is in g instead of mL/L. So it's quite confusing. I don't even know how to start.
I tried:
(.15M CaCl2)(.07L CaCl2)(1 mol CaCl2/2 mol AgNO3)
And that's about as far as I got, because I didn't even know if I was doing the right steps.

Any help is very appreciated.
 

Answers and Replies

  • #2
symbolipoint
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To be more sure, first compare the number of moles of CaCl2 to the number of moles of AgNO3; then, use the ratio information of 1 mole Calcuim Chloride to 2 moles Silver Nitrate to determine which compound is the limiting reactant.

Moles calcium chloride available = 0.07L * 0.15 M = ( )
moles silver nitrate available = 0.015L * 0.1 M = ( )

Which will one will still have a portion unreacted after mixing?
 

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