If 70.0 mL of 0.150 M CaCl2 is added to 15.0 mL of 0.100 M AgNO3, what is the mass in grams of AgCl precipitate?
The Attempt at a Solution
So I tried to find the limiting reagent, but that's where I'm stuck. I'm using examples from my textbook and notes, but everything is in g instead of mL/L. So it's quite confusing. I don't even know how to start.
(.15M CaCl2)(.07L CaCl2)(1 mol CaCl2/2 mol AgNO3)
And that's about as far as I got, because I didn't even know if I was doing the right steps.
Any help is very appreciated.