1. The problem statement, all variables and given/known data A large sphere exists in space, which has a mass of 1 * 10^28 kg The sphere has a radius of 100,000 km What will be its gravitational pull (aka: "relative gravity") on its surface in terms of gs (1 "g" being equal to the gravitational pull of the Earth which is 9.807 m/s^2)? 2. Relevant equations relative gravity = (gravitational constant * mass of object) / radius^2 gravitational constant = 6.67408 * 10^-11 m^3 kg^-1 s^-2 3. The attempt at a solution First I multiplied the Gravitational Constant by the object's mass: (6.67408 * 10^-11 m^3 kg^-1 s^-2) * (1*10^28 kg) = 6.67408 *10^17 m^3 s^-2 Next I squared the radius: (100,000,000 m)^2 = 1*10^16 m^2 Then I divided the numerator by the denominator: (6.67408 *10^17 m^3 s^-2) / (1*10^16 m^2) = 66.7408 m s^-2. This I define as the relative gravity upon the sphere's surface. Finally, I divided this relative gravity by the Earth's gravity: (66.7408 m s^-2) / (9.807 m s^-2) = 6.805 "gs" Thus: the gravitational pull upon this sphere's surface is about 6.805 times the gravity on the Earth's surface. Is my methodology and/or reasoning correct ladies & gentlemen?