Calculating Induced Current in Coaxial Solenoid-Wire System

[blur13]

I'm working on a question that I could use some help on. The problem basically says there is a solenoid with a current running through it given by an equation. There is a wire that is coaxial with and surrounding the solenoid, and the wire makes two loops around the solenoid. A resistance for the wire is also given. The question wants to know what the current in the wire is. Now, I know that if the wire was only looping around the solenoid once, I could just use faraday's law to calculate the induced emf, and then use I=$$\xi$$/R. What I can't figure out is how does the fact that there are two loops in the wire affect the induced current? Thanks for any replies.

 

[daniel_i_l]

The equation for induced current if the wire is wrapped n times around the magnetic field is:
$$I = \frac{\xi}{R} = \frac{n \dot{\phi_{t}}}{R}$$

 

[blur13]

Thanks for the quick reply. I'm just a tad confused about your notation. Are you saying that in this case I = 2$$\xi$$/R? Or that if the emf is known, then it is always simply I=$$\xi$$/R?

Edit: Oh, ok. I didn't see your edit there. Thanks for the help.