# Calculating Initial Charge

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1. Nov 3, 2014

### Quantum Fizzics

1. The problem statement, all variables and given/known data
Two small spheres with charges 1.6*10^-5 C & 6.4*10^-5 C, are 2.0m apart. The charges have the same sign. Where, relative to these two spheres, should a third sphere, of opposite charge 3.0*10^-6 C, be placed if the third sphere is to experience no net electrical force? Do we really need to know the charge or sign of the third object?
Given: q1 =1.6*10^-5 C
q2 = 6.4*10^-5 C
q3 = 3.0*10^-6 C
2. Relevant equations
F= kq1q2/d^2

3. The attempt at a solution
F31 = kq3q1/d^2
= 9x10^9*3.0x10^-6*1.6x10^-5/d^2

9x10^9*3.0x10^-6*1.6x10^-5 = d^2
0.657267069m= d

What I want to know is how will I know? If this will be the right distance where the 3rd sphere won't experience no net electrical force? That is the answer well ( 0.67m ) & yeah, because honestly we never learned this stuff in terms of coulombs law but I know that its the same as Newtons Law also I just gotta substitute some variables & such. An explanation would be great, thanks ( I got a quiz tomorrow so)

2. Nov 3, 2014

### elegysix

So you want the net force to equal zero. The net force = ?

By the way, it looks like you assumed F31 = 1 when you were solving for d.

3. Nov 3, 2014

### Quantum Fizzics

yeah, damn. Well I looked through my notes & I did it all wrong, I have to I guess make it into a complex trinomial & complete the square?(This is in terms newtons law, so I dont know how to transition that into coulombs law

4. Nov 3, 2014

### haruspex

As elegysix points out, to get that you seem to have assumed F31=1. You might have realised this made no sense if you had paid attention to the units or their dimensions. In the second equation above, the right hand side has dimension length squared, while the LHS has dimension time-squared * length / mass. It might also have occurred to you that you have not used any information regarding q2.

You are right that the charge of q3 is irrelevant. All you are looking for is where the fields due to q1 and q2 cancel. Write an equation for that.

5. Nov 3, 2014

### Quantum Fizzics

alright I got it now, is it okay to leave it as a decimal instead of keeping it into an exponent? or will that mess up everything

6. Nov 3, 2014

### haruspex

Since the answer looks likely to of the order of a metre, I would give the answer as a decimal.