1. The problem statement, all variables and given/known data For archery practice, a knight's squire drops sandbags from a 12.0 meter tower. At exactly the same time the sandbag is dropped, the knight shoots an arrow up at the sandbag from the base of the tower. If the arrow strikes the sandbag at exactly 1.1 seconds, calculate a) how far from the ground the arrow strikes the sandbag, and b) the arrow's initial velocity 2. Relevant equations d = ½(vi + vf)t vi = (d/t) – ((a x t)/2) 3. The attempt at a solution a) d = ½(-9.8)1.1 d = -5.39 12 - 5.39 = 6.61 The arrow strikes the sandbag at 6.6 m from the ground b) vi = (6.61/1.1) – (((-9.8) x 1.1)/2) vi = 6 – (-5.39) vi = 0.41 m/s Does this look right?