Calculating Ka

1. May 6, 2007

amcavoy

Using $$\Delta \textrm{E}^{\circ}$$ values and the fact that $$\textrm{K}_{\textrm{w}}=10^{-14}$$, how would I find the $$\textrm{K}_{\textrm{a}}$$ value for the following reaction?:

$$\textrm{HBrO}\longrightarrow\textrm{H}^{+}+\textrm{BrO}^{-}$$​

2. May 6, 2007

Noober

dEº = -RTlnK

Dunno if that helps :/.

3. May 6, 2007

Weave

Noobler sounds right.
Rearrange to give:
$$\frac{\Delta E}{-RT}=ln K_{a}$$
and solve for $$K_{a]$$

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