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Calculating Launch Angle

  1. Nov 1, 2011 #1
    1. The problem statement, all variables and given/known data
    Vy - 15m
    Vx - 40m
    U - 17m/s
    V - 0
    Time to reach highest point (t) 1.7s

    2. Relevant equations
    cos 0 = a/c

    3. The attempt at a solution
    72 degrees.

    Not sure if this is the correct method of calculating the angle, especially since a projectile's trajectory is a parabola.
  2. jcsd
  3. Nov 1, 2011 #2
    I am not following the problem's variables.

    Vy is usually velocity in the "y" direction in m/s

    Vx is usually velocity in the "x" direction in m/s

    What is U? It looks like some kind of velocity

    What is V? V usually designates some kind of velocity
  4. Nov 1, 2011 #3
    U = Initial Velocity
    V = Final Velocity, or Velocity at maximum height, hence 0

    I actually put the variables wrong, ignore the Vy should be Y and Vx should be X, hence, these aren't velocities, but instead ranges in the X and Y directions.
  5. Feb 20, 2012 #4


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