# Calculating Launch Angle

## Homework Statement

Vy - 15m
Vx - 40m
U - 17m/s
V - 0
Time to reach highest point (t) 1.7s

cos 0 = a/c

## The Attempt at a Solution

72 degrees.

Not sure if this is the correct method of calculating the angle, especially since a projectile's trajectory is a parabola.

Related Introductory Physics Homework Help News on Phys.org
I am not following the problem's variables.

Vy is usually velocity in the "y" direction in m/s

Vx is usually velocity in the "x" direction in m/s

What is U? It looks like some kind of velocity

What is V? V usually designates some kind of velocity

I am not following the problem's variables.

Vy is usually velocity in the "y" direction in m/s

Vx is usually velocity in the "x" direction in m/s

What is U? It looks like some kind of velocity

What is V? V usually designates some kind of velocity
U = Initial Velocity
V = Final Velocity, or Velocity at maximum height, hence 0

I actually put the variables wrong, ignore the Vy should be Y and Vx should be X, hence, these aren't velocities, but instead ranges in the X and Y directions.

berkeman
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