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Biology and Chemistry Homework Help
Calculating masses of unknown quantities of reactants.
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[QUOTE="thatguythere, post: 4542680, member: 441629"] [h2]Homework Statement [/h2] Calculate the number of moles and mass of BaCl[SUB]2[/SUB] and NaCl in the original mixture. [h2]Homework Equations[/h2] We prepared a solution of 0.35M Na[SUB]2[/SUB]SO[SUB]4[/SUB]. We then obtained an unknown mixture of BaCl[SUB]2[/SUB]•2H[SUB]2[/SUB]O and NaCl, weighed 1 g and added it to 200 mL of water and 10 mL HCl. Finally we added 10mL of the Na[SUB]2[/SUB]SO[SUB]4[/SUB] solution and heated the mixture for several minutes to form a precipitate which was then dried and weighed. Using the weight of the precipitate, which was 1.769 grams, we are asked to calculate the masses and mass percent of both BaCl[SUB]2[/SUB] and NaCl in the original mixture. The chemical equation given is: BaCl[SUB]2[/SUB](aq) + Na[SUB]2[/SUB]SO4 (aq) → BaSO[SUB]4[/SUB](s) + 2Na[SUP]+[/SUP](aq) + 2Cl[SUP]-[/SUP](aq)[h2]The Attempt at a Solution[/h2] Moles BaSO[SUB]4[/SUB]= 1.769gBaSO[SUB]4[/SUB] x (1 mol BaSO[SUB]4[/SUB]/233.39gBaSO[SUB]4[/SUB]) = .00768 moles BaSO[SUB]4[/SUB] Since the molar ratio between BaSO[SUB]4[/SUB] and BaCl[SUB]2[/SUB] is 1:1 Moles BaCl[SUB]2[/SUB]=0.00768 mol BaSO[SUB]4[/SUB] x (1 mol BaCl[SUB]2[/SUB]/1 mol BaSO[SUB]4[/SUB]) = 0.00768 moles BaCl[SUB]2[/SUB] Grams BaCl[SUB]2[/SUB]= 0.00768 mol BaCl[SUB]2[/SUB] x (208.23gBaCl[SUB]2[/SUB]/1 mol BaCl[SUB]2[/SUB] =1.60g BaCl[SUB]2[/SUB] This is what makes me believe I have done something quite incorrect, since the original mass of my mixture was only 1 gram. Please advise. Thank you. [/QUOTE]
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Biology and Chemistry Homework Help
Calculating masses of unknown quantities of reactants.
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