- #1
bullroar_86
- 30
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1. Show that the minimum stopping distance for a car traveling at speed v is equal to v^2 / 2*coefficient of friction*g, where the coefficient of static friction is between tires and the road and g is acceleration due to gravity.
I can re-arrange the equation Vf^2 = Vo^2 + 2ad to look the same as the above equation, since a = *coefficient of friction*g
Is that all this question is asking for? seems like I'm missing something here
thanks.
I can re-arrange the equation Vf^2 = Vo^2 + 2ad to look the same as the above equation, since a = *coefficient of friction*g
Is that all this question is asking for? seems like I'm missing something here
thanks.