1. The problem statement, all variables and given/known data Eighty-six proof whiskey is 43 percent ethyl alcohol, CH_{3}CH_{2}OH, by volume. If the density of ethyl alcohol is 0.79 kg/L, what is the molarity in whiskey. 2. Relevant equations Molar Mass of CH_{3}CH_{2}OH = 46.07 g 3. The attempt at a solution 0.79 kg/L * 1000 g/kg * 1 mole / 46.07 g = 17.15 M I was just looking for a check on this particular problem since I haven't taken a chemistry course since my freshman year ha!
Not bad - you are on the right track - but wrong. You have not used 43% in your calculations and this is an important information.
I thought you would have to use that 43% in there somewhere, but I'm not sure how to use it. It would be nice if I still owned my chem book. UPDATE: Ok I tried re-working the problem again, here's what I came up with: 0.79 kg/L * 0.43 L / 1 L * 1000 g / 1 kg * 1 mol / 46.07 g = 7.37 M how does that look?