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Calculating Moment of Inertia

  1. Apr 25, 2013 #1
    1. The problem statement, all variables and given/known data

    a)Find the moment of inertia about an axis that passes through mass A and is perpendicular to the page. In kg m^2

    b)Find the moment of inertia about an axis that passes through masses B and C.In kg m^2

    http://session.masteringphysics.com/problemAsset/1070524/4/12.EX16.jpg

    2. Relevant equations

    I=mr^2

    3. The attempt at a solution

    a) (Mass of a * r + Mass of b * r)/ (Total Mass)

    .005 They wanted the answer in two sigfigs so I put .05*10^-1 and it was wrong.

    b) Used Pythagorean Theorem

    sqrt(.10^2- .062)= .08
     
    Last edited: Apr 25, 2013
  2. jcsd
  3. Apr 25, 2013 #2

    Doc Al

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    Staff: Mentor

    Good. Just find I for each mass (around the given axis) and add them up to get the total I.

    You forgot to square the distances. What distance did you use? And why did you divide by the total mass?
     
  4. Apr 25, 2013 #3
    That makes sense, for some reason I was trying to find the center of mass which is completely irrelevant.

    The distances I used were for a were: (.1kg)(.1m)^2+ (.1kg)(.1m)^2


    The distance used for b was .08m (found using Pythagorean)
    (.08m)^2(.2kg)
     
  5. Apr 25, 2013 #4
    Thank you Doc Al, I appreciate it. Have a nice day.
     
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