(adsbygoogle = window.adsbygoogle || []).push({}); 1. It is known that the connecting rod AB exerts on the crank BC a 2.5kN force directed down and to the left along the center line of AB. Determine the moment of that force about C.

http://img267.imageshack.us/img267/6822/fic03p013hb0.png [Broken]

2. cross product

3.

I found the angle using tan-1 = 144/42 = 73.7

Fx = -2.5cos73.7 = -0.702

Fy = -2.5sin73.7 = -2.40

F = (-0.702i -2.40j + 0k)

CB = (-42i -56j + 0k)

F x CB= (-0.702i -2.40j + 0k) x (-42i -56j + 0k)

= -61.5 kN mm

does that seem right??????????????????????????

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# Homework Help: Calculating Moment

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