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Medicol
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1. A gene of length 4080 A° has 3120 hydrogen bonds. On one chromatid of one gene, there are 240 nucleotides of adenine, and 40% of total nucleotides are cytosine. Calculate each nucleotide percentage in the gene.
3. Set L be the length of DNA, so [tex]L=\frac{N}{2}3.4[/tex]
we then have [tex]N=2400[/tex].
Because [tex]C_1=G_2=0.4N=960[/tex]
and [tex]A_1=T_2=240[/tex]
we have [tex]A_2+C_2=1200[/tex]
In a DNA we also have [tex]∑Hbonds=2A+3G=2(A_1+A_2)+3(G_1+G_2)=3120[/tex]
or [tex]480+2A_2+3G_1+2880=3120[/tex]
or [tex]2A_2+3G_1=-240[/tex]
It's an incorrect approach...
Homework Equations
3. Set L be the length of DNA, so [tex]L=\frac{N}{2}3.4[/tex]
we then have [tex]N=2400[/tex].
Because [tex]C_1=G_2=0.4N=960[/tex]
and [tex]A_1=T_2=240[/tex]
we have [tex]A_2+C_2=1200[/tex]
In a DNA we also have [tex]∑Hbonds=2A+3G=2(A_1+A_2)+3(G_1+G_2)=3120[/tex]
or [tex]480+2A_2+3G_1+2880=3120[/tex]
or [tex]2A_2+3G_1=-240[/tex]
It's an incorrect approach...
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