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Calculating - PDF

  1. Sep 29, 2008 #1
    Determine constants A and B such that function f(x) is a valid PDF whose mean is 0.9 times its mode.

    f(x) = Ax- Bx ^3 , 0 <= x <= 2, otherwise = 0

    Also calculate its mean,median and mode and plot the PDF

    Please help...am scratching my head...have the answers but cannot derive the solution

    Answers : A = 0.8466 ; B = 0.1733 ; Mean = 1.1485 , Median = 1.1724 , Mode = 1.2761
  2. jcsd
  3. Sep 29, 2008 #2


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    What are the definitions of mean and mode for a PDF? Set mean=mode*0.9. That gives you one equation in A and B. Now remember a PDF needs to have integral=1 over it's domain. That gives you another equation for A and B. Solve them.
  4. Sep 30, 2008 #3
    got one fucntion...believe am screwing up in equating the mode and the mean i believe...mean is integral of x.f(x)dx right? basically integrate the function with limits 0 & 2...allright so u get 8A/3 - 32B/5 as Mean.....Mode....am doing df(x)/dx....i dont know if that is correct?? thanks though am getting a good picture now...just a lil twist needed..
  5. Sep 30, 2008 #4
    got it my friend...excellent help..thanks a lot buddy..take care
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