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Calculating pH of a base

  1. Sep 26, 2012 #1
    1. The problem statement, all variables and given/known data
    A strong base cane be assumed to be fully ionised in dilute solution. Use the Kw value to calculate the hydrogen ion concentration and hence the pH of a 0.15 M solution of potassium hydroxide, KOH.


    2. Relevant equations



    3. The attempt at a solution

    Problem is, I don't know where to begin, so any advice on how to proceed or pointers would be appreciated.
     
  2. jcsd
  3. Sep 26, 2012 #2
    Yeah, I think I managed to do it meself. Forgot it was a strong base.

    pOH=-log10[OH-]
    pOH=-log10[0.15M]
    pOH=0.824

    pH+pOH=14 ∴ pH=14-0.824=13.176
     
  4. Sep 26, 2012 #3

    Borek

    User Avatar

    Staff: Mentor

    Too many digits - 13.18 would be more to my liking. Other than that you did OK.
     
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