Calculating Potential Difference: Work Done and Kinetic Energy Relationship

[wikidrox]

Please assist me with this

The work done to move a 1.0 C charge from point P to Q is 3.0 * 10^-4J. If the charge starts from rest and has 1.0 * 10^-4J of kinetic energy when it reaches point Q, what must the potential difference be between P and Q?

For this would I use

Work done = kinetic + potential

therefore Potential difference = Work done - kinetic

This seems too simple to be right

 

[HeyHow!]

if i remember potential difference has something to do with Volts

 

[Doc Al]

potential versus potential energy

Work done = kinetic + potential

therefore Potential difference = Work done - kinetic

Don't confuse potential energy (PE) with potential difference (ΔV). The potential energy of a charge (Q) with respect to point at a lower potential (by ΔV) is PE = QΔV.