1. The problem statement, all variables and given/known data An escalator in a department store is designed to carry 300 passengers per minute from the ground floor to the mezzanine, 10m vertically higher. The design assumes an average weight per person of 70 kg. Allowing 30 percent loss for friction, calculate the power output which the driving motor must have. 2. Relevant equations KE = 0.5mv^2 3. The attempt at a solution So calculating the velocity of the escalator since it travels 10 meters in 60 seconds 10m/60 = 0.16667 m/s mass is 300 passengers * 70kg = 21000 kg work=0.5mv^2 = 291.167 J power = 291.167J/60 s = 4.86 W Is this good so far? 4.86 W is pretty low.