Calculating Probability of Sickle Cell Disease for Karen & Steve's Child

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SUMMARY

The probability that Karen and Steve's child will have sickle cell disease is calculated to be 1/9. Both Karen and Steve have siblings with sickle cell disease, indicating that their parents are carriers of the sickle cell trait. By analyzing the genetic cross of Ss x Ss, where S represents the normal allele and s represents the sickle cell allele, the probability of both parents being carriers is established at 1/2 each. The final calculation incorporates the probability of having a child with the genotype Ss, resulting in a total probability of 1/9 for the child to inherit sickle cell disease.

PREREQUISITES
  • Understanding of Mendelian genetics, specifically dominant and recessive traits.
  • Familiarity with Punnett squares for calculating genetic probabilities.
  • Knowledge of the sickle cell trait and its inheritance patterns.
  • Basic probability calculations in genetics.
NEXT STEPS
  • Study the principles of Mendelian inheritance in detail.
  • Learn how to construct and interpret Punnett squares for various genetic crosses.
  • Research the implications of being a carrier for genetic diseases like sickle cell anemia.
  • Explore advanced genetic probability calculations and their applications in genetic counseling.
USEFUL FOR

Individuals preparing for the MCAT, students studying genetics, genetic counselors, and anyone interested in understanding the inheritance of genetic disorders.

gravenewworld
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1. Karen and Steve each have a sibling w/ sickle-cell disease. Neither Karen nor Steve nor any of their parents have the disease, and none of them have been tested to reveal sickle-cell trait. Based on this incomplete information, calculate the probability that if this couple has a child, the child will have sickle cell disease.



1st off, I am not a student, but am just studying on my own to take the MCAT. I am not doing this for any class. The answer is 1/9, but I can not figure this one out. My reasoning thus far:

-So let S be dominant normal allele and let s be the sickle cell gene, which is a recessive trait.

-If Karen and Steve both have a sibling with sickle cell disease, then that means that both parents have to be carriers of the trait since it is a recessive gene. Thus if both parents of both Steven and Karen are carriers, then probability that Karen and Steve are carriers can be calculated from a SsxSs cross. That means that each of them has 1/2 chance of being a carrier.


-Since Karen and Steve don't have sickle cell, then the only way their kids can have sickle cell is if they have the Ss genotype. If they are both carriers, then they have 1/4 probability of having a child with sickle cell.


So the total probability of them having a child with sickle cell should be = Probability that Karen is a carrier x Probability that Steve is a carrier x Probability that they have a kid with sickle cell= 1/2 x 1/2 x 1/4 = 1/16.

I really don't see how 1/9 is the answer. Help please.
 
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gravenewworld said:
-If Karen and Steve both have a sibling with sickle cell disease, then that means that both parents have to be carriers of the trait since it is a recessive gene. Thus if both parents of both Steven and Karen are carriers, then probability that Karen and Steve are carriers can be calculated from a SsxSs cross. That means that each of them has 1/2 chance of being a carrier.

Incorrect. Try drawing out the Punnet square from a Ss x Ss cross and eliminating any possibilities you know to be wrong (i.e. because neither Karen nor Steve has the disease we know that the are not ss).
 
Alright thanks, Yggg. I see it now. Can't believe I missed this one.
 

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