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Mathematics
General Math
Calculating probability that 3 events occur 1 after other
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[QUOTE="HallsofIvy, post: 6788792, member: 637751"] That looks straight forward given what you wrote. There is a 0.5% chance A will occur so a 1.000- 0.005= 0.995 or 99.5% none of A, or B, or C will happen. There is a 0.5% chance A WILL happen and then a 1- 0.02= 0.98 or 98% chance B will NOT happen. There is a (0.005)(0.98)= 0.0049 or 0.49% chance A only will happen. There is a 0.5% chance A will happen and then a 2% chance B WILL happen. In that case there is a 1- 0.20= 0.80 or 80% chance C will NOT happen. So there is a (0.005)(0.02)(0.80)= 0.00008 or 0.008% chance of A and B but not C. Finally there is a (0.005)(0.02)(0.20)= 0.00008 or 0.008% chance that all three will happen. [/QUOTE]
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Mathematics
General Math
Calculating probability that 3 events occur 1 after other
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