This problem concerns calculating Reynold's Number of flow after exiting a duct. The duct that the flow exits is rectangular. The flow is measured directly underneath the center of the duct at a distance of 10 cm below the exit (Y-axis). Flow is measured at 11 m/s. It is determined that the velocity becomes 0 at a distance of 8 cm outward from the center (X axis). I am assuming that the flow is symmetric and thus the flow is esentially in a pipe with a radius of 8 cm.
Re = "rho"*V*d/"mu"
The Attempt at a Solution
"rho" = density = 1.20 kg/m^3
V = velocity of air = 11 m/s
d = diameter of pipe = 2*0.08m = 0.16 m
"mu" = viscosity of air = 1.8418e-05 kg/m*s
plugging those into the equation above yields: Re=1.147e+05
I guess my question is regarding my assumtion of the pipe. Was I correct in my assumption?