1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Calculating solubility

  1. Jun 30, 2009 #1
    1. The problem statement, all variables and given/known data
    Calculate the solubility of silver chloride at 25℃.

    Ksp of silver chloride at 25℃=1.8x10^-10

    2. Relevant equations
    AgCl⇔Ag+Cl (I believe)
    So, Ksp=[Ag][Cl]

    3. The attempt at a solution
    All I know is the Ksp of silver chloride at that temperature. I have no idea what to do from here. Do I need to know something about Ag or Cl?
     
  2. jcsd
  3. Jun 30, 2009 #2
    I attempted..
    Ksp=1.8x10^-10
    1.8x10^-10=[Ag][Cl]
    [Ag]=[Cl]=√1.8x10^-10
    =1.3x10^-5M

    So I got the solubility for both elements.. do I just add since AgCl⇔Ag+Cl?
     
  4. Jun 30, 2009 #3
    Okay, nevermind. 1.3x10^-5M is AgCl's molar solubility..
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Calculating solubility
  1. Lowering Solubility (Replies: 8)

  2. Constant of Solubility (Replies: 1)

Loading...