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Homework Help: Calculating solubility

  1. Jun 30, 2009 #1
    1. The problem statement, all variables and given/known data
    Calculate the solubility of silver chloride at 25℃.

    Ksp of silver chloride at 25℃=1.8x10^-10

    2. Relevant equations
    AgCl⇔Ag+Cl (I believe)
    So, Ksp=[Ag][Cl]

    3. The attempt at a solution
    All I know is the Ksp of silver chloride at that temperature. I have no idea what to do from here. Do I need to know something about Ag or Cl?
  2. jcsd
  3. Jun 30, 2009 #2
    I attempted..

    So I got the solubility for both elements.. do I just add since AgCl⇔Ag+Cl?
  4. Jun 30, 2009 #3
    Okay, nevermind. 1.3x10^-5M is AgCl's molar solubility..
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