1. The problem statement, all variables and given/known data Suppose 200 mg of PbCl2 was added to 15.0 mL of water in a flask, and the solution was allowed to reach equilibrium at 20.0 C. Some solute remained at the bottom of the flask after equilibrium, and the solution was filtered to collect the remaining PbCl2, which had a mass of 80 mg . What is the solubility of PbCl2 (in g/L)? 2. Relevant equations Not really sure: g solute/L of solution or g solute/L of solvent 3. The attempt at a solution I know how to solve this, but I was wondering if I'm supposed to include the the solute to the volume when finding solubility So amount dissolved = 200-80 = 120 mg 120 mg = 0.12 g 15 ml = 0.015 ml So is the answer: 0.12g/0.015 ml OR: 0.012g/(0.015 ml + 0.012 ml) Where 0.012 ml came from converting 0.012 g to ml.