(adsbygoogle = window.adsbygoogle || []).push({}); The question is this:

A 2 person tent is to be made so that the height at the center is 4 ft. if the sides of the tent meet at the ground at an angle of 60(degrees), and the tent is to be 6 feet in length, how many square feet of material will be needed to make the tent?

My answer:

Since it's a 60 degree angle, then it's a 30-60-90 triangle in which the smallest side is t, the side opposite of the largest side is 2t and the h is t x sq root of 3.

So t ends up being 4 x sq root 3 divided by 3

which means the width is 4.619 ft ( 4x1.732)/3 = 2.309 ft ~4.618 (since 2.309 is only half the length)

and 2t= 8(1.732)/3 = 4.619 ft

Now i just need help figuring out the sq feet. The answer in the book says 101.6 ft squard.

Any help is appriciated

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# Calculating square feet of a tent/triangle

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