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Homework Help: Calculating Standard Enthalpy

  1. Nov 18, 2009 #1
    1. The problem statement, all variables and given/known data

    4 C3H5N3O9 -> 12 CO2+10 H2O+6 N2 -- H rxn = -5678kJ

    Standard Heat of Formation of CO2=-394KJ
    Standard Heat of Formation of H2O=-242KJ

    Calculate the standard enthalpy of formation for nitroglycerin.

    2. Relevant equations

    Product minus reactant (I think)

    3. The attempt at a solution

    I thought you would swap this equation which gives 5678Kj. Then you have 12 moles of carbon dioxide and 10 moles of water (nitrogen is zero). Thus:

    5678- (-4728 - 2420)

    I think I'm way off though.
     
  2. jcsd
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