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bomba923

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**Area/Volume Question**

Given the function on a 3D coordinate system:

[tex] y = - z\sin \left( {xz} \right) [/tex] where [tex] \left| {x - \frac{\pi }

{2}} \right| \leqslant \frac{\pi }{z},\;z \ne 0 [/tex]

How do find the surface area of the figure integrated from z=a to z=b (where 'a' and 'b' are constants) ?

How would you also find the volume of this figure, from z=a to z=b (well, bounded by the top and by the trough, that is ) ?

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