# Calculating Surface Area

1. Oct 30, 2007

### amolv06

I need to find the surface area of z=$$x^{2}+2y$$ where 0$$\leq$$x$$\leq$$1 and 0$$\leq$$y$$\leq$$1. I figured it's like trying any other surface area problem, but I think I'm misunderstanding how to set up this problem. Here is what I tried:

$$\int^{1}_{0}$$$$\int^{1}_{0}\sqrt{2x+3}dydx = \frac{5\sqrt{5}}{3}-\sqrt{3}$$

However, my textbook says the correct answer is (3/2) + (5/8)ln[5]. Any help on where I went wrong would be appreciated.

Last edited: Oct 30, 2007
2. Oct 30, 2007

### amolv06

Heh, never mind, I seem to have made a dumb mistake. I forgot to square my partial derivatives.