1. The problem statement, all variables and given/known data In the circuit shown in the figure above, the ammeter reads 3.4 A and the voltmeter reads 6 V. Find the emf ɛ and the resistance R. 2. Relevant equations Ohm's law; V= I*R EMF equations: ε=I*r+I*R ε=I*r+V 3. The attempt at a solution I got the resistance of R right: It's 5.29Ω. To do that, I found the current in the 2Ω resistor (6V/2Ω=3A). Then, I know that since the 2Ω and the 4Ω resistors in are in series, the current in the two of them are equal. (4Ω*3A=12V). Then, I add up the two voltages (=18V), and solve for R using V=I*R, which gives me 18/3.4 = 5.2941Ω. However, when it comes to finding the emf, none of my answers are correct. I've tried "reducing" the circuit so it becomes 3 resistors in parallel (4Ω,2Ω and R on one side, 1Ω and the battery in the middle, and the 2 3Ω ones on the other side). However, this doesn't seem to give me the right answer. At first I thought it might be 6 volts since circuits in series are supposed to have the same voltage everywhere, but then I tried rationalizing it and it didn't work. Any push in the right direction would be greatly appreciated!