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Calculating the force resulted by pressure (integral)
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[QUOTE="CivilSigma, post: 4983974, member: 463654"] My thought to using integration is that the force applied to the piston changes as the depth changes. Pressure would change as the area changes correct? Pascals Law is A[SUB]1[/SUB]F[SUB]2[/SUB]=A[SUB]2[/SUB]F[SUB]1[/SUB] , but we are not given enough data to calculate area. So how do you propose solving this? [/QUOTE]
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Calculating the force resulted by pressure (integral)
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