I have recently done a titration lab, and I'm having some trouble figuring out what will happen to the Ksp value of Calcium Hydroxide. We were to use potassium hydrogen phthalate and calcium hydroxide. This is the equation I got: 2C8H5KO4 (aq) + Ca(OH)2 (aq) 2H2O (l) + Ca(C8H4KO4)2 (aq) The question for the lab is "What is the Ksp of Calcium Hydroxide at room temperate?" I have the calculations completed, but I'm having some trouble structuring the analysis. I was thinking that since C8H5KO4 is present, then the equilibrium will shift either left or right (this is where I am stuck), The Ksp value (3 x 10^-7) came out to be lower than the actual value (5.02 x 10^-6), so I assume that the equilibrium must have shifted right. <--- Not sure about this though.