1. The problem statement, all variables and given/known data The electrons in the beam of a television tube have an energy of 15 keV. The tube is oriented so that the electrons move horizontally from south to north. The vertical component of the Earth's magnetic field at the location of the television has a magnitude of 57.0 μT and is pointing down. a) In which direction does the force on the electrons act (enter N for north, S for South, E for East, or W for West)? Neglect a possible horizontal component of the magnetic field. b) What is the magnitude of the acceleration due to the vertical component of the Earth's magnetic field of an electron in the beam? c) If the inclination of the earth's magnetic field near the TV is 66deg, calculate the magnitude of the force on the electrons due to the horizontal component of the Earth's magnetic field. 2. Relevant equations B = qv x B 3. The attempt at a solution a) according to the right hand rule, it should be W. But apparently i am wrong. b) I got the answer which is 7.26 x 10^14 m/s^2 and also the F = 6.62 x 10^-16 N c) it should be 6.62x10^-16 x sin 66 right? I didn't get it right.